正規分布の四則演算

"1.054 571 68(18) × 10^{-34}" というのは「測定値は標準偏差を仮定すると平均 1.054 571 68 × 10^{-34} で 標準偏差 0.000 000 18 × 10^{-34} でしたよ」と言う意味で,正規分布の考え方が基礎になっている.では 1.203 (45) + 6.708 (91) は正規分布の性質をきちんと考えると「いくつ」か? (すなわち平均いくつ,標準偏差いくつの正規分布になるか?) これを四則演算に一般化するとかなりややこしい.(しかし上の計算も本当はこういう考えをしなければなるまい)

Some of the properties of the normal distribution:

  1. If X \sim N(\mu, \sigma^2) and a and b are real numbers, then a X + b \sim N(a \mu + b, (a \sigma)^2) (see expected value and variance).
  2. If X \sim N(\mu_X, \sigma^2_X) and Y \sim N(\mu_Y, \sigma^2_Y) are independent normal random variables, then:
    1. Their sum is normally distributed with U = X + Y \sim N(\mu_X + \mu_Y, \sigma^2_X + \sigma^2_Y) (proof).
    2. Their difference is normally distributed with V = X - Y \sim N(\mu_X - \mu_Y, \sigma^2_X + \sigma^2_Y).
    3. Both U and V are independent of each other.
  3. If X \sim N(0, \sigma^2_X) and Y \sim N(0, \sigma^2_Y) are independent normal random variables, then:
    1. Their product XY follows a distribution with density p given by
      p(z) = \frac{1}{\pi\,\sigma_X\,\sigma_Y} \; K_0\left(\frac{|z|}{\sigma_X\,\sigma_Y}\right), where K0 is a modified Bessel function of the second kind.
    2. Their ratio follows a Cauchy distribution with X/Y \sim \textrm{Cauchy}(0, \sigma_X/\sigma_Y).

それこそMathematica辺りでパッケージにまとまって何も考えずに使えるようにはなってないのか?